The major product of the following reaction i | vedclass

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(D) The reagent $NaBH_4$ (Sodium borohydride) is a selective reducing agent. It typically reduces aldehydes and ketones to alcohols,but it does not re

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$CH_3NH-CH_2-CH_2-CH=CH-CH(OH)-CH_3$

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(D) The reagent $NaBH_4$ (Sodium borohydride) is a selective reducing agent. It typically reduces aldehydes and ketones to alcohols,but it does not reduce isolated carbon-carbon double bonds $(C=C)$. However,it can reduce imines $(C=N)$ to amines $(C-NH)$. In the given molecule,there is an imine group $(CH_3N=CH-)$,a carbon-carbon double bond $(-CH=CH-)$,and a ketone group $(-CO-CH_3)$. $NaBH_4$ will reduce both the imine group and the ketone group,but it will leave the carbon-carbon double bond intact. Therefore,the product is $CH_3NH-CH_2-CH_2-CH=CH-CH(OH)-CH_3$.

The major product of the following reaction is:

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